Thursday, December 16, 2004

Math Problem I

Mount Pleasant, Iowa had a population of 8,751 people in the year 2000.

22.5% of the population was under the age of 18, and 14.1% of the population was 65 years of age or older.

11.5% of the population under the age of 18, and 9.4% of the population 65 years or older, lived below the poverty line.

1) How many children in Mount Pleasant under the age of 18 lived below the poverty line in the year 2000?

2) How many seniors, 65 years or older, lived below the poverty line in Mount Pleasant in the year 2000?

BONUS QUESTION: Assume that gay children are born to Mount Pleasanters as often as they are anywhere else, and that the birth rates of male and female children are equal. Estimating the rate of homosexuality in Mount Pleasant at one male in fourteen (7.1%), how many of Mount Pleasant's 8,751 residents are gay males, or future gay males, under the age of eighteen, who live below the poverty line?

See comments for answers.

3 comments:

Jessi Guilford said...
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Jessi Guilford said...

Question 1: 226.

(8751*.225*.115 = 226.43)

Question 2: 116.

(8751*.141*.094 = 115.99)

Bonus: 8.

(226.43/2/14 = 8.09)

stan said...

What would be the ideal social club that 8 gay or future-gay males under 18 living in poverty could form? I guess only 2 or 3 of them would be over 13. . . Those 3 could maybe watch movies together in someone's living room. . . I suppose roaming the streets wouldn't be a good option. . . Maybe the older ones could read books to the younger ones. . . I don't know what kind of books. What kind of books are there in Mt. Pleasant? Maybe they could have a club that engaged in seasonal sports? I suppose if you're below the poverty level, tobagganing is out. . .